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Can anyone help me with my math homework?
Solve the equation and check for extranneous solutions.
Sq. root of x^2-5 = 3-x
1 Answer
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- Tony GLv 51 decade agoFavorite Answer
Square both sides, which gives you:
x^2-5 = (3-x)^2 or x^2-5 = 9-6x+x^2
Set one side to equal zero so, in this case, subtract by -x^2+5 on both sides which will give you:
0 = 14-6x
Now solve for x:
6x = 14 --> x = 7/3
In this case, there are no extraneous solutions.
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