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Qugel
Qugel asked in Education & ReferenceHomework Help · 1 decade ago

If 3X2(g) -> 2X3(g), ΔH0 = -333kJ and atomic mass of X is 66.6 amu. What is ΔH of 11.1g of X3 -> X2 in kJ?

Can anyone calculate the ΔH? Please could you show the working out.

I have to pick one:

a. +2kJ

b. -2kJ

c. +9.25kJ

d. -333kJ

e. 9.25kJ

Thanks!

2 Answers

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  • dapo0130
    1 decade ago
    Favorite Answer

    CHEM1020 aye

  • gôhpihán
    Lv 7
    1 decade ago

    ΔH

    =number of moles * heat energy

    =11.1/66.6 * -333

    =-55.5kJ

    3 moles = -55.5kJ

    therefore 2 moles = -37 kJ

    I am 95% sure

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