Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Find any critical numbers of the function?
Question: Find any critical numbers of the function
The problem is f(X)=X(squared) * (X-3)
I've come to the conclusion that f'(X)=3X(X-2)
and I understand why 0 is an answer but why is 2 an answer too?
2 Answers
- 1 decade agoFavorite Answer
The definition of a critical number, are those points at which f '(x) = 0
And so if f '(x)=3x(x - 2)
Then we want to find:
0 = 3x(x - 2)
This equation is satisfied when x = 0:
f '(0) = 3(0)(0 - 2)
= 0
And also, when x = 2:
f '(2) = 3(2)(2 - 2)
= 3(2)(0)
= 0
- 1 decade ago
multiply it out and get x^3 - 3x^2=f(x)
derivative.
3x^2-6x= f ' (x)
solve for when f ' (x) equals zero.
which is 3x(x-2)
with x=0 and 2, for when f ' (x) equals zero, meaning its critical #'s
