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Michael M
Lv 6
Michael M asked in Science & MathematicsMathematics · 1 decade ago

Please show me the steps to solve this.?

Sorry. I left out some symbols

If 3x^2 – 2x + 7 = 0, then (x – 1/3)^2=

Update:

If 3x2 – 2x + 7 = 0, then (x – 13)2=

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  • JB
    Lv 7
    1 decade ago
    Favorite Answer

    First divide by 3:

    x^2 - (2/3) x + (7/3) = 0.

    Now transpose the (7/3) and then add the square of one half the coefficient of x to complete the square, i.e. add 1/9 to both sides.

    x^2 - (2/3) x + 1/9 = -7/3 + 1/9

    (x - 1/3)^2 = -7/3 + 1/9 = -21/9 + 1/9 = -20/9.

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