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Michael M
Lv 6
Please show me the steps to solve this.?
Sorry. I left out some symbols
If 3x^2 – 2x + 7 = 0, then (x – 1/3)^2=
Update:
If 3x2 – 2x + 7 = 0, then (x – 13)2=
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- JBLv 71 decade agoFavorite Answer
First divide by 3:
x^2 - (2/3) x + (7/3) = 0.
Now transpose the (7/3) and then add the square of one half the coefficient of x to complete the square, i.e. add 1/9 to both sides.
x^2 - (2/3) x + 1/9 = -7/3 + 1/9
(x - 1/3)^2 = -7/3 + 1/9 = -21/9 + 1/9 = -20/9.
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