how do i write a general linear equation for the line through the two points (0,0) and (2,3)?

slope is rise over run.

in ur case, 2/3.

slope is 2/3

using the formula y=mx+b where m is slope and b is y-intercept,

ur equation is: y=(2/3)x + 0

since i answered first, i should get best answer.

You want a slope m and a y-intercept b such that the line y = mx + b passes through a given point (x1, y1), (x2, y2). m is "rise over run", i.e.

m = (y2-y1) / (x2 - x1).

To find b, you want it so that y1 = m x1 + b. In the latter equation, you know everything except b, for which you solve: b = y1 - m x1.

Slope: (y2-y1)/(x2-x1)

= (3-0)/(2-0) = 3/2

m = 3/2

Choose one set of coordinates and do point-slope form.

(0, 0) is easier. The other coordinates would come out with same answer (it's all on the same line).

y-y1=m(x-x1)

y-0=3/2(x-0)

y=3/2x

1. find the slope (y2-y1)/(x2-x1)

2. it's 3/2. sorry for spoiling it :P

3. since there is no y influction, there is no b in the equation mx+b

4. y=3/2x

Hope that's it. i have no calculator

(3/2)= (y-3)/(x - 2); simplify and you got your answer