How do I find this integral ∫ ∫ ∫ ∫ ∫ ∫ (z+Z)/|r+R|³ dxdydz dXdYdZ?

Question

∫ ∫ ∫  ∫ ∫ ∫ (r+R)/|r+R|³ dxdydz dXdYdZ 
where vectors r and R are
r = (x,y,z)  
R = (X,Y,Z)
and |r+R| is absolute value of vector r+R
|r+R| = √[(x+X)² +(y+Y)² + (z+Z)²]

Integration is done inside upper half of unit sphere, that is
0 < z, Z 
0 < R, r < 1

? · Accepted Answer

Changing the variables (X, Y, Z) -> (-X, -Y, -Z), one reduces the integral to

I = ∫ ∫ f(r, R) dr dR, f(r,R) = (z-Z) / |r - R|^3,

where r lies in the upper hemisphere z>0, and R lies in the lower hemisphere Z<0. Integral of f over r and R lying in the same area is equal to zero, because swapping r and R in this case gives

∫ ∫ f(r, R) dr dR = ∫ ∫ f(R, r) dR dr = - ∫ ∫ f(r, R) dr dR.

Hence, one can perform the integration over dR inside the unit sphere. For r<1, this integral is equal to the vertical electric field inside a sphere with a unit charge density,

g = ∫ f(r, R) dR = (4 π /3) z.

To get the answer, integrate g over the upper hemisphere,

I = ∫ g dr =

= (4 π /3) ∫ ρ^3 cosθ sinθ dρ dθ dφ =

= π^2 / 3.

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How do I find this integral ∫ ∫ ∫ ∫ ∫ ∫ (z+Z)/|r+R|³ dxdydz dXdYdZ?

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