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Conic equations with an extra y variable?
I've been trying to figure this out for awhile, I was sick the last few days of school and have no idea how to do this.
x^2 + y^2 - 10y = 11
I'm thinking it's a circle, but how do you graph the equation with the -10y there? How do you solve it so that it's graphable?
1 Answer
- PeteLv 41 decade agoFavorite Answer
to solve you need to complete the square
you got an extra Y, and you need it to turn it into (y+a)^2
now y^2-10y+25 is a perfect square of (y-5)^2, so since we are missing an +25, we added to both sides of the equation to keep it the same.
you'll get
X^2+(Y-5)^2=36
since its a + between the x and y squares, we know that its an eplise, with the center at (0, 5) [since x^2 can be seen as (x-0)^2]
since both coefficients are same on x and y, its an circle, with a radius of 6
