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Help with division of polynomial?
x^3+3x^2-4x+3 divided by x+1
Please explain how to get the answer. Thanks a bunch!
The answer is x^2+2x-6, remainder 9
I need to understand how to get the answer
4 Answers
- Jun AgrudaLv 71 decade agoFavorite Answer
= (x³ + 3x² - 4x + 3)/(x + 1) yields x²
= x³ + 3x² - 4x + 3 - (x³ + x²)
= x³ + 3x² - 4x + 3 - x³ - x²
= (2x² - 4x + 3)/(x + 1) yields 2x
= 2x² - 4x + 3 - (2x² + 2x)
= 2x² - 4x + 3 - 2x² - 2x
= (- 6x + 3)/(x + 1) yields - 6
= - 6x + 3 - (- 6x - 6)
= - 6x + 3 + 6x + 6
= 9
Answer: x² + 2x - 6 & 9/(x + 1)
- Anonymous1 decade ago
Since x+1 is degree 1 use synthetic division:
-1 | 1 3 -4 3
__ -1-2 6____
1 2 -6 | R:9
so x^2 + 2x + 2 + 9/(x+1)
- 1 decade ago
x + 1 = 0
x = -1
so...
-1]
1 3 -4 3
+ (1)(-1) (0)(-1) (2)(-1) (-6)(-1)
_______________________________
0 2 -6 9
2x^2 - 6x + 9 = 0
FINAL ANSWER:
(2x^2 - 6x + 9) / (x+1)
- Anonymous1 decade ago
x^2 + 2x + 6
____________
x+1 | x^3+3x^2-4x+3
x^3+x^2
---------------------------
2x^2-4x+3
2x^2+2x
--------------------------
-6x+3
6x+6
_____________
-3
---------------------------
so quotient= x^2 + 2x + 6
remainder= -3
Source(s): lower standard mathematics
