Algebraically solve 3x minus 11√x minus 4 =0?

If \/'''x''''=y

then, 3y^2 -11y-4=0

y=[11+&-(121+48)^1/2]/6=4 & -1/3

then, \/''x'''=4

x=16, check, 48-44-4=0 , x=16 is acceptable

\/''x''=-1/3, check, x=1/9. 1/3-11(\/'''-1/3''') \/'''x'''=-1/3 NOT ACCEPTABLE.

God bless you.

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