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ניקול
Lv 4
ניקול asked in Science & MathematicsMathematics · 1 decade ago

How do you solve these logarithmic functions?

1) log x= -2

2) log(3x+5)= 2

They seem so simple but my teacher didn't lecture very well on this... Can you please explain how to do them?

2 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    You haven't indicated the base of the logarithms, so in these cases we assume the base is 10.

    1) 10^-2 = x, or x = 1/100

    2) 3x+5 = 10^2,

    i.e. 3x+5 = 100,

    so x = 95/3

  • nozar nazari
    Lv 7
    1 decade ago

    1) x=10^-2=1/100

    2) 3x+5=10^2=100 , 3x=95 , x=95/3=31.67

    God bless you.

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