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related rates calculus problem?
a heart attack victim has been given a blood vessel dilator drug to lower the pressure. for a short while after the drug is given, the radii of the blood vessels will increase by about 1% of the radius/min. According to Poiseuille's Law V=k r^4, what percentage rate of increase can we expect in the blood flow?
but i need the answer using related rates and derivatives please.
another answerer said:
for the second question on the blood flow rate, what is not clear to me, and maybe you have a better answer on this (if your specialty is in biology, pharmaceuticals or medicine), is if the increase in the radii of a blood vessel due to the dilator drug follows a population increase model (like in question 1) or a linear increase model. What I found out in either case outlined below, the rate of increase in blood flow is the same within a given level of accuracy for the first few minutes. to highlight this follow:
Population increase mode (or exponential increase):
r(t) = r0 * (1.01)^t, where r0 is the initial radii of a blood vessel.
V(t) = k * r(t)^4 = k * (r0 * (1.01)^t )^4
= k * r0^4 * (1.01)^(4t)
you can think of V0=k*r0^4 as the initial blood flow level before the drug is applied
therefore,
V(t) = V0 * (1.01)^(4t)
and the second term is the increase
Percentage Increase = ((1.01)^(4t) - 1)*100
For linear model:
r(t) = r0 * (1+0.01*t), where r0 is the initial radii of a blood vessel.
V(t) = k * r(t)^4 = k * (r0 * (1+0.01*t))^4
= k * r0^4 * (1+0.01*t)^4
you can think of V0=k*r0^4 as the initial blood flow level before the drug is applied
therefore,
V(t) = V0 * (1+0.01*t)^4
and the second term is the increase
Percentage Increase = ((1.01)^(4t) - 1)*100
For the first few minutes, both models will give similar results.
t (min) %
0 0%
1 4%
2 8%
3 13%
4 17%
5 22%
1 Answer
- PurepotatoLv 41 decade agoFavorite Answer
If k is a constant,
dV/dt = k(4r³)dr/dt
dr/dt = 0.01r (1% of the radius every minute)
dV/dt = 4kr³(0.01r)
=0.04kr^4