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Algebra II Functions?
We barely went over functions today in class, and I know how to do them for the most part, except when the problems are like this:
The initial functions:
f (x) = 2x + 4
g (x) = -3x +5
And then I get problems like this and get stuck:
1. 3f(x)
2. 3[f(x)]^2
The work shown would be much appreciated. There are many problems like both of those on the paper, I would just like to see how to work them out so I can figure out the rest.
Thanks!
2 Answers
- Anonymous1 decade agoFavorite Answer
We have f(x) = 2x+4, g(x) = -3x+5
1. Then 3f(x) = 3(2x+4) = 6x+12
2. 3(f(x))^2 = 3(2x+4)^2
=12x^2+48x+48
- MDeniseLv 51 decade ago
In problems like what you gave, just substitute 2x+4 for f(x) and -3x+5 for g(x) and simplify.
3f(x) = 3(2x + 4) = ...
3[f(x)]² = 3(2x+4)² = ...
