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Can you help me with this math question?

"The sum of two numbers is 17 more than their difference. What are the two numbers?" If you can answer this, can you teach me how to get the answer? Thank you.

4 Answers

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  • Favorite Answer

    set up:

    x+y=x-y+17

    to find y

    x+y=x-y+17

    = y=-y+17

    = 2y=17

    = y=17/2=8.5

    to find x

    (8.5)+17=x

    = 25.5=x=51/2

    check

    25.5+8.5=25.5-8.5+17

    34=34

  • jsjs
    Lv 5
    1 decade ago

    Let the two numbers be x and y, with x >= y. Then the given information says that

    x + y = 17 + x - y.

    Note that we can cancel out the x's, so this equation is equivalent to the equation

    y = 17 - y.

    We have a problem; this equation gives us no information about x, so we can't determine what x is. Are you sure you copied the entire problem? We can still solve for y:

    y = 17 - y

    2y = 17

    y = 17/2 = 8.5.

    We conclude that one of the numbers is 8.5, and the other could be any number greater than or equal to 8.5.

  • Anonymous
    1 decade ago

    x + y = x - y + 17

    2y = 17

    y = 8.5

    Any differential of 17 (x +/- 8.5) will give you a value for x except for 17, 0

    (x would = 8.5) start at 18, 1

    if x + 8.5 = 18

    then x - 8.5 = 1 (add equations)

    2x = 19

    x = 9.5

    if x + 8.5 = 20

    then x - 8.5 = 3 (add equations)

    2x = 23

    x = 11.5

  • 1 decade ago

    I have an addition to your first answer: Since you know that y=8,5, then x has to be 17 more than that or 25.5.

    Proof by substitution:

    25.5 + 8.5 = 17 + 25.5 - 8.5

    34 = 42.5 - 8.5

    34 = 34

    Source(s): old Math teacher
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