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mitchell_bball
mitchell_bball asked in Education & ReferenceHomework Help · 1 decade ago

How do you solve the equation (d + square root d) -132 = 0?

I really need this answered ASAP plz help

Update:

sorry that should be:

d + (square root d) - 132 = 0

3 Answers

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  • :)smiles:)
    1 decade ago

    121=d

    121+11=132-132=0

    Source(s): http://www.wolframalpha.com/input/?i=%28d+%2B+squa...
  • Ruff Lindy
    Lv 5
    1 decade ago

    let square root d be some random letter, like "x".

    so then it would be:

    x^2+x-132

    (x-11)(x+12)

    sub back

    sqrt d - 11=0

    sqrt d + 12=0

    d=sqrt11

    second one is undefined

  • Anonymous
    1 decade ago

    (d + [SR]d) - 132 = 0

    d + [SR]d=132

    d[SQUARED] + d = 17424

    uuuh thats all i THNK i know

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