Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
why is the intergral of 16/(x^2)... -16/x?
what steps did you do for this? u substitution?
3 Answers
- 1 decade agoFavorite Answer
Bring up the x^2 so you have the integral of 16x^-2. Put the 16 outside the integral sign so that you have only x^-2 inside the sign. Now follow the rules for integration- add 1 to -2 and the denomination of x^-2 has to have -2+1 also. You now have 16x^-1 over -1 which can be written as -16x^-1 which can be changed to -16/x
- 1 decade ago
You don't need u substitution for this one. You just use the regular rule for integrals, as follows:
Integral of 16x^2 - 16x = 16 * x^3/3 - 16 * x^2/2 = (16x^3)/3 = 8x^2.
- sunset8949Lv 41 decade ago
16 / x^2 = 16(x^-2)
Antiderivative would then be 16(x^(-2+1)) / (-2+1)
16(x^-1) / -1
-16 / x
