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Can somebody help me with Algebra 2 work please?
the problems are:
2x^2 + 9x + 7 = 0
16x^2 + 16x + 4 = 0
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- hayharbrLv 71 decade agoFavorite Answer
(2x + 7)(x + 1) = 0
so 2x + 7 = 0; 2x = -7; x = -7/2
or x + 1 = 0; x = -1
4(4x^2 + 4x + 1) = 0
4(2x + 1)(2x + 1) = 0
so 2x + 1 = 0; 2x = -1; x = -1/2
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