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solving for tangent line vertical and horizontal from a function?
y= x^3 -2yx^2 +y^2 = -1
at (-1,2)
i have the line tangent:
(y-2)=(-5/2)(x+1)
so how do you find the tangent line vertical and tangent line horizontal?
show your work please.
3 Answers
- 1 decade agoFavorite Answer
horizontal lines have equal slopes
vertical lines have slopes that are negative reciprocals of one another
- Anonymous7 years ago
confusing stuff look into over yahoo or google just that can help
- Anonymous5 years ago
Use Quadratic formula? X= (b^2 plus or minus square root of the discriminant)/2a Discriminant is b^2-4ac
