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physics numerical problem vector?
two particles r located at r1=3i^+7j^ and r2=-2i^+3j^respectively. find both the magnitude of vector (r2-r1) and its orientation with respect to x axis?
the ans is 6.4 and 219 degree!
i just dnt no how to work it out
2 Answers
- ?Lv 71 decade agoFavorite Answer
it's clear that r2 - r1 = (-2 - 3)i + (3 - 7)j = -5i - 4j
so mag = sqrt(-5^2 + -4^2) = sqrt(41) = 6.4
theta = arctan(-4/-5) = 219 degrees
- 1 decade ago
you just subtract the i^ and j^ components of . and then use these formulas to get the magnitude and direction of the resultant vector:
magnitude= sqrt of [(i component)^2 +(j component)^2]
direction= Arctangent [ (j component)/(i component)]
