Factor these eqations. Please show work.?

A) (h-3)(h+2)

B) -3v^9-3^8+36v= -3(v^9+1-12v)=3(v+4)(v-3)

C) (m-2)(m-2)

D) (4t-3)(3t-2)

you cant show work for the first two but you can for D

you use this method:

in an ax^2+bx+c equation where a is greater than one you multiply the c value by a to get 12t^2-17t+72

then set up the equation like this

(12t-#)(12t-#)

------------------

12

then you use the basic method of what two #'s multiply to get 72 but add up to -17 in this case they are -9 and -8

now simplify

(12t-9)(12t-8)

----------------

12

3(4t-3)4(3t-2)

-----------------

12

(4t-3)(3t-2)

now check

(4t-3)(3t-2)=12t^2 -17t +6

A. h^2-h-6 = (h-3)(h+2)

B. -3v^9-3^8+36v= -3(v^9+1-12v)=3(v+4)(v-3)

C. m^2-4m+4= (m-2)(m-2)=(m-2)^2

D. 17 is a prime number so I would suggest that you use the quadratic equation to factor it. If you don't know the quadratic equation it is as follows: -b plus or minus the square root of b^2-4ac divided by 2a. A is the value that is raised to a power, b is the linear term or the number with the variable raised to no power and that leaves c as the number that does not have a variable attached to it.

A) (h-3)(h+2)

C) (m-2)(m-2)