What is the answer to this problem?PLZ ANSWER!!!!?

Please Excuse My Dear Aunt Sally. This is the first thing that you should think of when doing problems like this. It is the order of operations. P = parentheses E= exponents M = multiply D = divide A = add and S = subtract. When you look at this equation, you should instantly notice there are 2 brackets and 2 parentheses. Brackets are always before parentheses. So first you do everything inside the bracket, but wait, there are two parentheses inside the bracket, this means we should do whatever is in the parentheses first. Lets look inside the parentheses, hey look, there is a power, that is next in the order of operations. 3 to the 2nd power is 9. Lets see what we have so far 200/ [ 11+3(4+9)]. Since 4+9 is still in a parentheses we do that which is 200/ [ 11+3(13)]. Inside the bracket we multiply 13x3.

200/ [ 11+39]. Almost there. There are still brackets so we take 11+39. 200/[50]. Since we have nothing left in the bracket we can now divide. 200/50= 4. Hope this helps!

Learn the Orders of Operations:

http://mathforum.org/library/drmath/view/69146.htm...

http://mathforum.org/library/drmath/view/66614.htm...

Parentheses, exponents, multiplication/division, addition/subtraction.

You can't combine the 4 and 3^2 right away. Do the exponent first to get 4+9, which gives you:

200 / [11 + 3(4 + 3^2)]

200 / [11 + 3(4 + 9)]

200 / [11 + 3(13)]

Now do the inner-most parentheses

200 / [11 + 39]

Then the next set:

200 / 50

Finally, just divide 200 by 50 to get 4.

your brother is right

200/[11+3(4+3^2)]

200/[11+3(4+9)]

200/[11+3(13)]

200/(11+39)

200/(50)

4

its the order of operations

Please Excuse My Dear Aunt Sally

Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

PEMDAS:

Parenthesis (inner then outer)

Exponents

Multiply/Divide

Add/Subtract

doing the inner parenthesis: (4+3^2)=4+9=13

outer parenthesis: (11+3*13)=50

division: 200/50=4

200/(11+3x(4+3^2))=200/(11+3x(4+9))=200/(11+3x(13))

=200/(11+39)=200/50=20/5=4