Need help with an algebra problem!!?

2(t+5t)=48

First use the distributive property: 2t+10t=48

Add like terms: 12t=48

Divide both sides by 12:t=4

Answers is: t=4

First multiply the 2 by t and 5t which equals 2t+10t=48 then you add the 2t and the 10t together because they are like terms and that will equal 12t=48 so divide 12t into 48 then think what can 12 multiply to equal 48 so them you say 12 goes into 48, 4 times so your answer would be t=4. Then plug the 4 into where t is at to make sure its the right answer so 2((4)+5(4))= 48, so it would be 8+40=48. So 4 is your answer to what t is.

My guess is that you are solving for the unknown variable t in the above equation.

The first step would be add the common elements in the parenthesis.

i.e. 2*(t+5*t) = 48 becomes --> 2*(6*t) = 48

You can do this step because the variable "t" plus five of the variable "t" ---> = 2*(t+t+t+t+t+t) which is equal to six of those t's or ---> 2*(6*t)

The next step would be to multiply 2 times the 6 (as a side note, the six is defined as a coefficient, which just denotes the number of t's you currently have).

This gives you: 12*t = 48

The next step in this equation is to use an "inverse operation." One rule of thumb is that is you preform a arithmetic operation to both sides of the equation, that equation is still the same as before (just with a different ratio).

The inverse operation that would be helpful for this situation would be to divide both sides of the equation by 12.

This would produce a final answer of t = 4.

Hope this helps!!

You distribute the 2 to the t and 5t. In this case, you end up with 2t + 10t = 48

or 12t=48

then just divide by 12 to get 1t by itself,

12/12t=48/12

t=4

solve the sum inside the bracket first.

2(6t)=48

multiply it with the no. outside the bracket

2*6t=12t=48

to know the value of t take 12 to the other side.thus * becomes / as we should take the opposite sign when we change sides.

t=48/12=4

First distribute the outside term

2t+10t=48

then combine like terms

12t=48

divide to isolate term

t=4