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B-Rad
Lv 4
B-Rad asked in Science & MathematicsMathematics · 1 decade ago

College Algebra word problem?(4)?

'The length of a proposed rectangular flower garden is 4 feet less than five times the width. The area of a proposed garden is 57 ft^2. Find the length of the proposed flower garden.

Thanks for all of your help guys...

2 Answers

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  • I'm with Stupid
    Lv 7
    1 decade ago
    Favorite Answer

    let

    x = length (ft)

    y = width (ft)

    so

    x = 5y - 4

    and

    xy = 57

    so

    (5y - 4)y = 57

    5y² - 4y - 57 = 0

    (y + 3)(5y - 19) = 0

    reject negative solution, so

    y = 19/5

    and

    x = 15

    length = 15 ft.

    ♣♦

  • ?
    Lv 4
    5 years ago

    J=John's velocity (mph) G=George's velocity (mph) john can rigidity 240miles on the comparable time because it takes george to rigidity 220 miles: (240 mi)/J=(220 mi)/G=time john drives 5mph quicker than george J=G+5 There are 2 equations and a pair of unknowns. resolve them concurrently. 240/(G+5)=220/G 240G=220*(G+5) 240G=220G+1100 20G=1100 G=55 mph J=55+5 J=60 mph

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