Trig help! 10 pts best answer!?

Use parentheses to show what all is in the denominator. I think you mean:

x/(x - 3) - 2/(3x + 4)

If so, the common denominator is (x - 3)(3x + 4)

x/(x - 3) - 2/(3x + 4)

(3x + 4)x/((x - 3)(3x + 4)) - (x - 3)2/((x - 3)(3x + 4))

(x(3x + 4) - 2(x - 3)) / ((x - 3)(3x + 4))

(3x^2 + 4x - 2x + 6) / ((x - 3)(3x + 4))

(3x^2 + 2x + 6) / ((x - 3)(3x + 4))

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This is more of an algebra problem that could be applied in a trigonometric context.

I would multiply each of the terms by [(x-3)(3x+4)]/[(x-3)(3x+4)]

In essence, we want to multiply each of the terms by 1. :)

x/x-3 - 2/3x+4

= [x/(x-3)]*[(x-3)(3x+4)]/[(x-3)(3x+4)] - [2/(3x+4)]*[(x-3)(3x+4)]/[(x-3)(3x+4)]

= [x ]*[ (3x+4)]/[(x-3)(3x+4)] - [2 ]*[(x-3) ]/[(x-3)(3x+4)]

= (3x^2+4x - 2x-6) / [(x-3)(3x+4)]