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Cosa
Cosa asked in Science & MathematicsMathematics · 1 decade ago

Have coffee that is $7/lbs, have 14lbs of coffee that is $4/lbs. Need mixture for $5/ lbs.?

Have coffe that is $7/lbs, have 14lbs of coffe that is $4/lbs. Need mixture for $5/ lbs.

Please help. how do i solve this?

2 Answers

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  • M3
    Lv 7
    1 decade ago
    Favorite Answer

    use minimum variables !

    -----------------------------------

    let x lbs of coffee @ $7/lb be added, then

    7x + 4*14 = 5(x+14)

    7x - 5x = 14(5 - 4)

    2x = 14

    x = 7 lbs

    -------------

  • Ralph 124c41
    Lv 6
    1 decade ago

    Let

    P(1) = price of coffee 1

    W(1) = weight of coffee 1

    P(2) = price of coffee 2

    W(2) = weight of coffee 2

    Then the formula for the value of the mix would be the value of each component divided by the total weight

    P = (P(1)W(1)+P(2)W(2))/(W(1)+W(2)

    Assume you need to use all 14 lbs of $4 coffee

    5 = (7W(1)+4×14)/(W(1)+14)

    5(W(1)+14) = (7W(1)+4×14)

    5W(1)+70 = 7W(1)+56

    2W(1) = 14

    W(1) = 7

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