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?
Lv 4
? asked in Science & MathematicsBiology · 1 decade ago

Can someone please answer this Q and show me the punnet square?

In humans, normal pigmentation dominates no pigmentation (albino). Black hair dominates blonde hair. An albino person will have white hair, even though he/she may also have the alleles for black or blonde hair. An albino male who is homozygous for black hair marries a woman who is heterozygous for normal pigmentation and had blonde hair. What colors of hair can their children have, and what is the probability fro each hair color?

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  • Anonymous
    1 decade ago
    Favorite Answer

    You need pigmentation to show the hair color. It doesn't matter if a person is supposed to have black hair or blond hair, if there's no gene for pigmentation, the color won't show.

    Let's look at the pigmentation or no pigmentation first. Let's say P is pigmentation and p is no pigmentation.

    albino male: pp

    normal woman: Pp

    Their children: pP, pp, pP, pp

    it means, half the children will have pigmentations while the other half will be albino.

    Now, let's look at their color alleles. Let's say B is black and b is blond

    black hair male: BB

    blond woman: bb

    children: all Bb.

    All children will be heterozygous black hair.

    Answer: 50% of children will be albino or white hair. 50 % of children will have pigmentation and they will have black hair.

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    1

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  • ?
    Lv 4
    5 years ago

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    7 years ago

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    7 years ago

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  • Anonymous
    5 years ago

    Let's say X' is affected by color bind. Let's look at 3 children's genotype Child A: X'Y (he's colorblind) Child B: X'X' (both of her allele is affected because she's color blind) Child C: X' X (Because if you look at Child B, she receives X' from mother and X' from father. Child C still receives X' from father but X from mother so she is not affected) Now let's look at their parents Their X' comes from mother because boy gets X' from mother and Y from father. Look at Child B. Both of them are affected. She gets X' from mother and X' from father. Genotype Father: X'Y Mother: X X' Phenotype: Father: color blind male Mother: Normal female

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