Help with Trig question?

[(2x^2 * x) - (x * x) + (3 * x)] + [(2x^2 * 3) - (x * 3) + (3 * 3)]

(2x^3 - x^2 + 3x) + (6x^2 - 3x + 9)

2x^3 + 5x^2 + 9

first change the equation to wear it looks easier:

(x+3)(2x^2-x+3)

then multiply the x with all three numbers from the equation in pareanthesis, givng you:

2x^3 - x^2 + 3x

then do the same with the 3 from the (x+3), giving you:

6x^2 - 3x + 9

then combine like terms, leaving you with the answer of:

2x^3 + 5x^2 + 9

2x^2 (x+3) -x(x+3) +3(x+3)

= 2x^3 + 6x^2 -x^2 -3x + 3x + 9

[6xsquared minus 1xsquared equals 5xsquared, and negative 3x plus 3x gives us 0 so...)

= 2x^3 +5x^2 + 9

I hope I did this right, it's hard to do it on the computer..

2*x^2*(x) = 2*x^3

2*x^2*(3) = 6*x^2

( - x)*(x) = - x^2

( - x)*(3) = - 3*x

3*x = 3*x

3*3 = 9

2*x^3 + 6*x^2 - x^2 - 3*x + 3*x + 9 = 2*x^3 + 5*x^2 + 9, Answer.