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Can you solve this probability problem?
Mr. A and Mrs. B are involved in a tournament. The probability that Mr. A will win is 2/5, and the probability that Mrs. B will win is 1/3. What is the probability that neither one will win?
It would be greatly appreciated if you could show how you got this answer. Thanks!
1 Answer
- KeplJoeyLv 71 decade agoFavorite Answer
There are three possible outcomes to consider here: Either Mr A wins, Mrs B wins, or neither wins.
Since one of these three things must happen, the probabilities of these three events must add to 1.
So if we denote the probability of neither winning as P(Neith), the probability of Mr A winning as P(A) and the probability of Mrs B winning as P(B) then
P(Neith) = 1 - P(A) - P(B).
But you're given P(A) = 2/5
P(B) = 1/3
So P(Neith) = 1 - 2/5 - 1/3
= 15/15 - 6/15 - 5/15
= 4/15.
