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Factor a^2-c^2+b^2+2ab?
Factor completely. Your answer must be expressed as a product of two polynomials.
I would greatly appreciate if you show how you get your answer.
I don't know if this helps, but I've noticed that this equation can be made into the law of cosines...
2 Answers
- Lummox JRLv 41 decade agoFavorite Answer
Move the similar terms together and you should see a pattern:
a^2 + 2ab + b^2 - c^2
The a and b terms form a perfect square, with the formula (a+b)^2 = a^2 + 2ab + b^2.
(a+b)^2 - c^2
This leaves you with a difference of squares, whose formula is (a+b)(a-b) = a^2 - b^2.
(a+b+c)(a+b-c)
- ?Lv 71 decade ago
cute
your teacher hates you
LOL
you are going to end up with a 'difference of squares'
which become 'two polynomial'
never mind the polynomial has more than what you think it should
so,
a^2-c^2+b^2+2ab
move -c^2 to the end
a^2+b^2+2ab-c^2
rewrite as
a^2+2ab+b^2-c^2
factor a^2+2ab+b^2
(a+b)^2
gives you
(a+b)^2-c^2
difference of squares
((a+b)+c)*((a+b)-c)
(a+b+c)*(a+b-c)