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Probability of an event in series?
If a trial event has a 38% chance of succeeding, what is the probability of obtaining one success in three trials? How about two successes in three trials?
M3 - I don't suppose you could translate that into English?
Are you saying there's a 43.8% chance of hitting one out of three, and 26.8% of hitting two out of three?
1 Answer
- M3Lv 71 decade agoFavorite Answer
apply the binomdist formula with n = 3, p = 0.38, q = 0.62
P[1] = C(3,1) * 0.38^1 * 0.62^2
= 0.438216
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P[2] = C(3,2) * 0.38^2 * 0.62^1
= 0.268584
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