balancing out chemical equation problem?

C8H18+O2 = CO2+H2O

You've got 8 carbons on the left, so you need 8 carbons on the right:

C8H18 + O2 = 8 CO2 + H2O

You've got 18 hydrogens on the left, so you need 18 hydrogens on the right:

C8H18 + O2 = 8 CO2 + 9 H2O

Now you've got 25 oxygens on the right, but oxygens on the left only come in even numbers, so double everything and try again:

2 C8H18 + O2 = 16 CO2 + 18 H2O

Now you've got 50 oxygens on the right, so you need 50 oxygens on the left:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

i ought to furnish you some suggestion on balancing out equations generaly: >get the equation > draw containers around the seperate compounds[ this could remind you to multiply finished field by skill of the selection] >do a style of element inventory ,or checklist >attempt to observe paterns, and discover numbers to multiply with eg.fermentation of glucose; [C6H12O6] >>> [CH3CH2OH] + [CO2] ______________________ in the previous reaction > AFTER reaction C : 6 > 3 H : 12 > 6 O : 6 > 3 start to observe a patern... if we if we multiply each little thing on the suited by skill of two it rather is all equivalent! [C6H12O6] >>> 2 [CH3CH2OH] + 2[CO2]