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R3al!ty !s s0 b0r!ng
Lv 5
R3al!ty !s s0 b0r!ng asked in Education & ReferenceHomework Help · 1 decade ago

Algebra 1 help (wordproblems)?

I have to solve this problem, but I really can't figure it out.

Kelly bought games and books. Games costs $6 each while books are only $7 each. If kelly spent $51 and only ended up with 8 items, how many games and books did kelly buy?

Any help's appreciated(: Thanks !

3 Answers

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  • Matt
    Lv 5
    1 decade ago
    Favorite Answer

    6g + 7b = 51

    g + b = 8

    so

    g = 8 - b

    6(8 - b) + 7b = 51

    48 - 6b + 7b = 51

    b = 3

    g + 3 = 8

    g = 5

  • Bonnie L
    1 decade ago

    buy x books and y games

    6y+7x=51

    y+x=8, so y=8-x

    bring back to the first equation

    6y+7x=51

    6(8-x)+7x=51

    48-6x+7x=51

    48+x=51

    so x=3, so y=5

  • ?
    1 decade ago

    5 games and 3 books... hahaha it was a lucky guess for me :)

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