How do you simplify these polynomials/monomials?

[(3²)²]³

Take it in steps.

First do 3². Then square the answer. Then take it to the (third? eighth?) power and you should have your answer.

b(4b - 1) + 10b

4b² - b + 10b (I just distributed)

4b² + 9b is your answer.

a million): escalate and simplify: 8d - 4d(7d + a million) + 4(d - 6 + d^2) = 8d -4d(7d) -4d(+a million) +4(d) +4(-6) +4(d^2) = 8d -28d^2 -4d +4d -24 +4d^2 = -24d^2 + 8d -24 2): hint a million: (a^m)^n = a^(m*n) hint 2: (a^m)*(a^n) = a^(m+n) hint 3: (a^m)/(a^n) = a^(m-n) A = [(2a^5b^2c^6d^3)^2 (4ab^3cd^5)^3] / [8a^4b^3cd^6] A = [[(2)^2 (a^5)^2 (b^2)^2 (c^6)^2 (d^3)^2] [(4)^3 (a)^3 (b^3)^3 (c)^3 (d^5)^3]] / [8 a^4 b^3 c d^6] A= [ 2^2 * a^10 * b^4 * c^12 *d^6 * 4^3 *a^3 * b^9 * c^3 * d^15] / [2^3 a^4 b^3 c d^6] A= [ (2^2 *4^3) * (a^10 * a^3) (b^4 * b^9) (c^12 * c^3) (d^6 * d^15)] / [2^3 a^4 b^3 c d^6] A = [[(2^2 *(2^2)^3)] * a^(10+3) * b(4+9) * c^(12+3) * d^(6+15)] / [2^3 a^4 b^3 c d^6] A = [[(2^2 * 2^(2*3)] a^13 b^13 c^15 d^21] / [8 a^4 b^3 c d^6] A = [[(2^2 * 2^6)] a^13 b^13 c^15 d^21] / [2^3 a^4 b^3 c d^6] A = [[(2^(2+6)] a^13 b^13 c^15 d^21] / [2^3 a^4 b^3 c d^6] A = [2^8 a^13 b^13 c^15 d^21] / [^3 a^4 b^3 c d^6] A= [2^8 / 2^3] [a^13 / a^4] [b^13 / b^3] [c^15 / c^a million] [d^21 / d^6] (hint 3) A= [2^(8-3)] [a^(13-4)] [b^(13-3)] [c^(15-a million)] [d^(21-6)] A = [2^5] [a^9] [c^14] [b^10] [d^15] A = 32a^9 b^10 c^14 d^15