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I need help with statistics homewood re: the chi-square and phi coefficient?
Can someone please explain how to do this problem? I need steps please.
Silverlake Boys Republic
Did not recidivate 85 25
Recidivated 60 75
1) Chi-square
a. 18.18
b. 27.32
c. 19.26
2.) Phi-Coefficient
a. 0.33
b. 0.28
c. 0.65
3.) Interpret the Phi-Coefficient (i.e., is there a relationship? How strong or weak is it?)
a. weak
b. moderate
c. strong.
2 Answers
- cidyahLv 71 decade agoFavorite Answer
1)
Observed frequencies:
--------85--------60--------25--------75
Row 1 total = 145
Row 2 total = 100
Column 1 total = 110
Column 2 total = 135
Grand total 245
Expected frequencies
E(1,1) = (145)(110) / 245 = 65.102
E(1,2) = (145)(135) / 245 = 79.898
E(2,1) = (100)(110) / 245 = 44.898
E(2,2) = (100)(135) / 245 = 55.102
Expected frequencies:
--------65.102--------79.898--------44.898--------55.102
Chi-square = Σ [O(i,j)-E(i,j)]^2 / E(i,j)
(85 - 65.102)^2 /65.102 + (60 - 79.898)^2 /79.898 +
(25 - 44.898)^2 /44.898 + (75 - 55.102)^2 /55.102
6.0817+4.9554+8.8184+7.1854+
Chi-squared = 27.32
Degrees of freedom = (2-1)(2-1) =(1)(1) = 1
--------------------------------------
2)
85 25 --110
60 75---135
145 100 -- 245
Qhi-coefficient
n11 n10 n1.
n01 n00 n0.
n.1 n.0 n
Phi = (n11n00 -n10n01) / sqrt[n1.n0.n.0n.1]
= [ (85)(75)-(25)(60)] /sqrt [ (135)(110)(100)(145)]
= 0.33
3)
weak
-----------------------
* -1.0 to -0.7 strong negative association.
* -0.7 to -0.3 weak negative association.
* -0.3 to +0.3 little or no association.
* +0.3 to +0.7 weak positive association.
* +0.7 to +1.0 strong positive association.
- ?Lv 44 years ago
Flavour predicted values talked approximately values index Vanilla 25% 220/one thousand = 22% a million Chocolate 25% 255/one thousand = 25.5% 2 Strawberry 20% one hundred ninety.one hundred = 19% 3 Butter Pecan 15% a hundred and seventy/one thousand = 17% 4 Rocky street 8% ninety 5/one thousand = 9.5% 5 different or no pref. 7% 70/one thousand = 7% 6 --------- ---------------------- one hundred% one hundred% Chi sq. = Sum of [{ talked approximately(i) - predicted(i)}^2]/predicted(i) E. g Sum of [(22 -25)^2]/ 25 + [(25.5 - 25)^2]/25 ................... ranges of Freedom = 5 you will now could seek for suggestion from a table of Chi sq. for 5 ranges of freedom to verify in the journey that your hypothesis I put in the element because of the fact i don't comprehend ways conventional you're with the notation. All superb desires Polygon