solve for x y=bx-c- need help, please!?

y=bx-c

Add 'c' to both sides it gives

y+c=bx-c+c

or y+c=bx

now divide both sidesby 'b' giving

(y+c)/b=bx/b

i.e (y+c)/b=x

or b= (y+c)/b

Given y = bx - c, solve for x.

First, attempt to isolate x by adding c to both sides. We have:

y + c = bx

Lastly, to isolate for x, divide both sides by b:

∴ x = (y + c) / b

Your objective here is to get x alone. So,since x is with a b (bx),first get bx alone.

1)Add both sides by c.

y+c=bx (c here is cancelled.)

2)Since bx is now alone, we have to get x alone.

Divide both sides by b.

Then, the answer will be

x=(y+c)/b

To solve for x, make x the subject of the equation:

y = bx - c

y + c = bx

Ans: x = (y+c)/b

y=bx-c

Add c to each side of equaton

y + c = bx

Divide both sides of equation by b

y/b + c/b = x

x = y/b + c/b = (y + c)/b

y = b*x - c

Solve for x means isolating it!

y + c = b*x

x = (y + c)/b

x = (1/b)*y + c/b

y=bx-c

y+c

----- = x

b