csc^ * x/2 = 2secx??

mm is the problem csc^(x/2) = 2 secx?

OR (csc^x)/2= 2 sec x?

can you please rewrite the question to clarify thanks :)

****im so sorry one more thing.. are you trying to solve for x or prove that one side equals the other?

okay i LOVE trig but this has to be one of the weirdest questions ive ever worked on.. so far this is what i got.. but i did get stuck on the last part.. so i couldnt quite finish the entire thingg :(( im super sorry.. but anywho...

so, my goal is to bring (x/2) down so apply log on both sides.

csc^(x/2) = 2 sec x

(x/2) log csc x = log 2 sec x <-- ( i put the extra "x" in front of the csc cause im pretty sure theres suppose to be an "x")

so,

(x/2) log csc x = log 2 sec x

now divide log csc x on both sides & not that sec= 1/cos & csc= 1/sin

(x/2) = log 2 sec x/ log csc x

(x/2) = log 2 (1/cos x)/(1/sin x)

multiply by the reciprocal for (1/cos x)/(1/sin x) so,

(x/2) = log 2 tan x

***also note that sin/cos = tan

now multiply 2 on both sides so,

x = log 4 tan x???

& from there i got stuck :((( im super sorry!!!! i tried showing my friends & they also said this is a weird problem :(( seriously recommend asking your teacher! cause i would like to know what the solution is too lols.

BUT if you have any other questions feel free to email me.