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differentiate sin x/ x^2?
= [x^2 d/dx (sin x) - sinx d/dx (x^2) ] / (x^2)^2
= [ x^2(cosx) - (sinx) (2x)] / (x^2)^2
what do i do next
the answer is (x cosx - 2 sinx) / x^3
3 Answers
- ComoLv 710 years agoFavorite Answer
By Quotient Rule dy/dx is given by :-
x ² cos x - sin x (2x)
----------------------------
x^4
x cos x - 2 sin x
----------------------
x^3
- RapidfireLv 710 years ago
Expand the denominator then cancel common factors to get the answer:
f'(x) = (x²cosx - 2xsinx) / (x²)²
f'(x) = (x²cosx - 2xsinx) / x⁴
f'(x) = x(xcosx - 2sinx) / x⁴
f'(x) = (xcosx - 2sinx) / x³
