Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Craps Game Probability?

I don't usually ask for help on math problems but I am truly stumped on this one.

In a game of craps, you roll two fair dice. Whether you win or lose depends on the sum of the numbers occurring on the tops of the dice. Let x be the random variable that represents the sum of the numbers on the tops of the dice.

What is the probability distribution of these x values (that is, what is the probability that x = 2, 3, etc.)? (Round your answers to three decimal places.)

Probability of x=2?

Probability of x=3?

Probability of x=4?

Probability of x=5?

Probability of x=6?

Probability of x=7?

Probability of x=8?

Probability of x=9?

Probability of x=10?

Probability of x=11?

Probability of x=12?

3 Answers

Relevance
  • Anonymous
    10 years ago
    Favorite Answer

    x=2, 1/36 or .028

    x=3, 1/18 or .056

    x=4, 1/12 or .083

    x=5, 1/9 or .111

    x=6, 5/36 or .139

    x=7, 1/6 or .167

    x=8, 5/36 or .139

    x=9, 1/9 or .111

    x=10, 1/12 or .083

    x=11, 1/18 or .056

    x=12, 1/36 or .028

  • 4 years ago

    Thats a soreness interior the dick you may parent the probibility of no longer triumphing for each factor, and then evaluate how in many circumstances each and each factor is the factor in accordance with its probibility of rolling in the process the pop out roll. You cant confirm the probibility based on the Nth roll era, because of the fact the sport transformations after the 1st comeout, you could parent a fastened probibility of triumphing for the 1st roll, and then use a variable for all next rolls. in case you paypal me 50 funds unwell parent it out for you and supply you very particular counsel.

  • ?
    Lv 6
    10 years ago

    There are only 36 numbers possible.

    One 2 (1,1) = 1 out of 36

    two 3s (1,2) (2,1) = 2 out of 36

    three 4s ( 1,3) (2,2) (3,!)

    four 5s (1,4) (2,3) (3,2) (4,1)

    five 6s (1,5) (2,4) (3,3) (4,2) (5,1)

    six 7s ( 1,6) (2,4) (3,4) (4,3) ( 5,2) (6,1)

    five 8s ( 6,2) (5,3) (4,4) (3,5) (2,6) = 5 out of 36

    four 9s

    three 10s

    two 11s

    one 12 (6,6)

Still have questions? Get your answers by asking now.