Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
oscillation question, easy one!?
The earths free fall acceleration varies from 9.78m/s at the equator to 9.83 m/s a the poles. A pendulum whose length is precisely 1.000M can be used to measure g. Such a Device s called a gravimeter.
A.) How long do 100 oscillations take at the equator?
B.) How long do 100 oscillations take at the north pole?
C.) Suppose you take your gravimeter to the top of a high mountain peak near the equator. There you find that 100 oscillations takes 201 seconds. What is g on the mountain top?
I am sure that this is a easy question but its stumping me. Thanks!!
1 Answer
- 10 years agoFavorite Answer
You should simply apply the pendulum period formula:
T = 2π√(L/g)
A) L = 1.000 m, g = 9.78 m/s²
T = 6.283 √(1.000 / 9.78) = 2.009 s
100 T = 200.9 s
B) L = 1.000 m, g = 9.83 m/s²
T = 6.283 √(1.000 / 9.83) = 2.004 s
100 T = 200.4 s
C) 100 T = 201 s
T = 2.01 s
g = 4π²L / T² = 4 * 3.1416² * 1.000 / 2.01² = 9.77 m/s²