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How many four-digit numbers can be formed from the digits 1 and 2 if repetitions are allowed?

I know it's 16, I've listed them out. But I need to know how to get the answer actually using the proper formulae. This is for A level Statistics, specifically permutations! If anyone can give me a worked answer, or explain, please do!

7 Answers

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  • 9 years ago
    Favorite Answer

    Hi Caro,

    Consider the four digit number digit-by-digit.

    Digit one: two possibilities, 1 or 2.

    Digit two: two possibilities, 1 or 2.

    Digit three: two possibilities, 1 or 2.

    Digit four: two possibilities, 1 or 2.

    The total number of possibilities is the product of the possibilities of the digits.

    Total possibilities = 2 * 2 * 2 * 2 = 2^4 = 16.

    -----

    More generally, an n-digit number with m possibilities for each digit will have:

    Total possibilities = m^n.

  • 4 years ago

    For a variety to be divisible by ability of 11. Sum of wierd place numbers = sum of even place numbers As repetition is authorized thus, 1111 may be the 1st variety and 5555 may be the final variety. So sum of wierd place numbers or perhaps place numbers ranges from 2 (in 1111) to ten (in 5555). No. of numbers with sum 2 = a million No. of numbers with sum 3 = 4 a threat with digits a million and a pair of Numbers like 1122, 1221 , 2112, 2211. So 4 numbers. No. of numbers with sum 4 = 9 a threat with (2,2) and (a million,3) With (2,2) = a million basically ( 2222) With (a million,3) = 4 ( like in previous case) With (a million,3) and (2,2) = 4 ( 1232, 3212, 2123, 2321) No.of numbers with sum 5 = sixteen a threat with (a million,4), (2,3) and (a million,4,2,3). Now it follows a trend. LIke a million, 4, 9, sixteen, 25, sixteen, 9, 4, a million So answer = a million+4+9+sixteen+25+sixteen+9+4+a million = eighty 5 answer is E NONE of those

  • 9 years ago

    2^4

  • Anonymous
    9 years ago

    2*2*2*2

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  • ?
    Lv 4
    9 years ago

    1111

    1112

    1121

    1122

    1211

    1212

    1221

    1222

    2111

    2112

    2121

    2122

    2211

    2212

    2221

    2222

    yup you answered it correctly

    it's 16

  • 9 years ago

    Unit place can be filled by two given numbers = 2

    Tenth place can be filled by two given numbers = 2

    Hundredth place can be filled by two given numbers = 2

    thousand place can be filled by two given numbers = 2

    Therefore total number ways = 2x2x2x2 =2^4 =16 ways ................Ans

  • 9 years ago

    Using the BASIC COUNTING Principle, multiply

    the number of choices (2) for EACH place holder (4)

    ___ x ___ x ___ x ___

    _2_ x _2_ x _2_ x _2_ = 16

    ANSWER.....16

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