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How many four-digit numbers can be formed from the digits 1 and 2 if repetitions are allowed?
I know it's 16, I've listed them out. But I need to know how to get the answer actually using the proper formulae. This is for A level Statistics, specifically permutations! If anyone can give me a worked answer, or explain, please do!
7 Answers
- bobbyjimthefirstLv 59 years agoFavorite Answer
Hi Caro,
Consider the four digit number digit-by-digit.
Digit one: two possibilities, 1 or 2.
Digit two: two possibilities, 1 or 2.
Digit three: two possibilities, 1 or 2.
Digit four: two possibilities, 1 or 2.
The total number of possibilities is the product of the possibilities of the digits.
Total possibilities = 2 * 2 * 2 * 2 = 2^4 = 16.
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More generally, an n-digit number with m possibilities for each digit will have:
Total possibilities = m^n.
- 4 years ago
For a variety to be divisible by ability of 11. Sum of wierd place numbers = sum of even place numbers As repetition is authorized thus, 1111 may be the 1st variety and 5555 may be the final variety. So sum of wierd place numbers or perhaps place numbers ranges from 2 (in 1111) to ten (in 5555). No. of numbers with sum 2 = a million No. of numbers with sum 3 = 4 a threat with digits a million and a pair of Numbers like 1122, 1221 , 2112, 2211. So 4 numbers. No. of numbers with sum 4 = 9 a threat with (2,2) and (a million,3) With (2,2) = a million basically ( 2222) With (a million,3) = 4 ( like in previous case) With (a million,3) and (2,2) = 4 ( 1232, 3212, 2123, 2321) No.of numbers with sum 5 = sixteen a threat with (a million,4), (2,3) and (a million,4,2,3). Now it follows a trend. LIke a million, 4, 9, sixteen, 25, sixteen, 9, 4, a million So answer = a million+4+9+sixteen+25+sixteen+9+4+a million = eighty 5 answer is E NONE of those
- Anonymous9 years ago
2*2*2*2
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- ?Lv 49 years ago
1111
1112
1121
1122
1211
1212
1221
1222
2111
2112
2121
2122
2211
2212
2221
2222
yup you answered it correctly
it's 16
- Amar SoniLv 79 years ago
Unit place can be filled by two given numbers = 2
Tenth place can be filled by two given numbers = 2
Hundredth place can be filled by two given numbers = 2
thousand place can be filled by two given numbers = 2
Therefore total number ways = 2x2x2x2 =2^4 =16 ways ................Ans
- 9 years ago
Using the BASIC COUNTING Principle, multiply
the number of choices (2) for EACH place holder (4)
___ x ___ x ___ x ___
_2_ x _2_ x _2_ x _2_ = 16
ANSWER.....16