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Quadratic function in vertex form?
y=3x^2-12x+1
step by step plz
2 Answers
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- answerINGLv 69 years agoFavorite Answer
y=3x^2-12x+1 = 3 [x² - 4x ] + 1 = 3 [x² - 4x + (2²)] + 1+ (-12) putting
the parentheses' pieces in is completing the square (and adding zero) to leave
the original function unchanged. Now
y = 3 [x - 2]² - 11 so the parab opens up(because of the pos coeffic 3); the vertex is (2, -11)
- Anonymous9 years ago
convert to y = 3(x-b)^2 + c , find b , c
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