How do I express this surd?

(2+√3)³

(2+√3)² * (2+√3)

(4+4√3+3)(2+√3)

(7+4√3)(2+√3)

26+15√3

a.) ?2 / 2 2 may well be expressed as (?2 x ?2), so this turns into: ?2 / (?2 x ?2) between the basis twos cancel, to furnish a million / (?2) b.) Root six may well be written ?2 x ?3, so as that 2 / ?6 = 2 / (?2 x ?6) lower back the two on the numerator may well be written as (?2 x ?2), one in each of which cancels with the basis 2 on the denominator giving: (?2 / ?3) we can not have a surd as a denominator so we ought to multiply the two the numerator and denominator by ?3, giving: (?6 / 3)

( 2+root3)^3 square it first and get 4 + 4root 3 +3 = (7 +4root 3) now multiply by( 2+root 3)

(7+4root3)(2+root3) = 14+7 root 3 +8root3 +12 = 26 +15 root 3

(2 + root 3)^3

= (2+ root 3)(2+ root 3)(2+ root 3)

= (4 + 4 root 3 + 3)(2+ root 3)

= (7 + 4 root 3)(2 + root 3)

= (14 + 7 root 3 + 8 root 3 + 4(3))

= (26 + 15 root 3)