How many times more intense is an earthquake that measures 7.5 on the Richter scale than one that measures 6.7?

7.5 - 6.7 = 0.8

10^0.8 ≅ 6.309573445

The 7.5 earthquake is approximately 6.3 times as intense as the 6.7 earthquake

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How to figure it using your equation:

M = log(i/s)

10^M = i/s

i = s·10^M

ratio of the intensities of the two earthquakes = (s·10^7.5)/(s·10^6.7)

= 10^(7.5-6.7)

= 10^0.8

≅ 6.3:1

properly the two yet they do no longer look to be probably comparable. A seismograph is an tool that measures the quantity of shaking at even though place it relatively is. by using itself it could no longer tell a lot with reference to the capability of an earthquake because of the fact it relatively is measurements are tormented by using its distance from the epicenter. The farther away the earthquake, the weaker the measurement. The Richter scale is a equipment for estimating the capability of an earthquake according to quite a few diverse aspects. one way it is accomplished is to evaluate the measurements of quite a few diverse seismographs that are located a diverse factors around the earth. by using noting the time that the sign reaches each and each tool and the plain capability of each sign geologists can hit upon the epicenter and then calculate the capability of the earthquake based length of each sign and the area to each and each seismograph. So in a fashion the seismograph is somewhat like the yardstick and the Richter scale is somewhat like the contraptions the yardstick is calibrated in inclusive of inches. The Richter value of an earthquake is likewise each so often expected by using examining the aftereffects. it is considerable in determining the capability of an earthquake that exceeded off earlier seismographs have been invented.