An aircraft whose speed in still air is 350km/h flies in a straight line from A to B, a distance of 480 km?

Question

There is a wind of 50 km/h blowing from the north. The pilot sets a course of 130 degree. Calculate the time taken to fly form A to B and the bearing of B from A. 
I don't know how to answer this cuz I haven't learned this before. Anyone can help me? I don't really need the exact answer. Just tell me how to get the answer :)

Julian · Accepted Answer

you have to find the relative speed to the ground = V

Vx = 350cos40 = 268.11
Vy = 350sin40 + 50= 275
V² = Vx² + Vy²
V = 384 km/h
V*t = 480 ==> t = 480/384 = 1.25 h  ==> answer
bearing of B from A 
tan(Angle) = Vy/Vx = 275/268.11 = 
Angle = 45.73°
bearing = 90° + 45.73° = 135.73° ==> answer

jacob s · Answer

480*(h/350)=48/35=1.37 hr


So the bearing from B to A is 130° + 180° or 310°.

Anonymous · Answer

Hi

it is somehow complicated dude, u know

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An aircraft whose speed in still air is 350km/h flies in a straight line from A to B, a distance of 480 km?

3 Answers