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Factoring polynomials?
Factor the polynomial by grouping the middle term of an equivalent trinomial has already been written
10s^2+15s+4s+6=
32b^2-20bq+24bq-15q^2
Factor completely
2c^2-7c-14c+49=
3w^2+14w+8
6s^2+29s-42
10c^2-29C+10
Complete the factoring
6a^2+11ab-35b^2=(2a+7b) ( )
I am trying to do a final review and these have me stuck! Can some one please walk me threw how to solve I would greatly greatly apperciate it
2 Answers
- ?Lv 79 years agoFavorite Answer
Look for common factor
10s² + 15s + 4s + 6
Common factor of (10s² + 15s) is 5s; Common factor of (4s + 6) is 2
= 5s(2s + 3) + 2(2s + 3)
= (2s + 3)(5s + 2)
-----------------
= 32b² - 20bq + 24bq - 15q²
= 4b(8b - 5q) + 3q(8b - 5q)
= (8b - 5q)(4b + 3q)
----------------------
2c² - 7c - 14c + 49
= c(2c - 7) - 7(2c - 7)
= (c - 7)(2c - 7)
------------------
3w² + 14w + 8
I can rewrite as
3w² + 12w + 2w + 8
3w(w + 4) + 2(w + 4)
(w + 4)(3w + 2)
--------------------
You can do the rest.
- 9 years ago
when something is squared (^2) multiply that number by itself. for example 6a^2 would be this in factored form- 36aa. once you have those, just combine the like terms. whether that's through addition or subtraction
