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solve complex number?
How does 50/(32+j24) be (1 - j0.75)...is the the wrong? show working out with explanation if possible..cheers!
2 Answers
- 9 years agoFavorite Answer
first you must move i out if the denominator by multiplying by 32-24i/32-24i which ='s 1, so
(remember that 32-24i and 32+24i are complex conjugates
50/(32+24i) * 32-24i/32-24i = 50(32-24i)/ (32+24i)(32-24i ,for the denominator recall that a difference of squares
a^2-b^2= (a-b)(a+b) a=32 and b =24i, so 32^2 - (24i)^2 = 1024 - 576*i^2, i^2= -1, so 1024 - 576 * -1 =
1024 + 576 = 1600, now for the numerator 50(32-24i) use the distributive property, = 1600-1200i
so (1600-1200i)/1600 (That's Nice lol!) 1600/1600= 1 and 1200i/1600 = .75i so
(1600-1200i)/1600= 1-.75i.
I hope this was helpful!
Source(s): Pre calc student - DambarudharLv 79 years ago
50 / (32 + j24)
= 50 / {8(4 + j3)
= {50(4 - j3)} / {8(4 +j3)(4 - j3)}
= {50(4 - j3)} / {8*25)
= (4 - j3) / 4
= (1 - j0.75)
