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need help with the logarithm problem!!!!?
If loga x = 2, loga y = 6, and loga z = −2, then find loga [ (x^2)(z^3 )] / square root[ (y) ] .so all those terms are in the same bracket just the x and z term for the numerator and the y term in the denominator, with the log a outside of them
thank you barredo and sarp, i really appreciate you helping me out with this, thanks for going step by step, made it really easy
2 Answers
- βαяяϵdθLv 79 years agoFavorite Answer
loga [ (x^2)(z^3 )] / √y ]
loga x^2 + loga z^3 - loga √y
2 loga x + 3 loga z - 1/2 * loga y
=> 2 (2) + 3 (-2) - 1/2* (6)
=> 4 - 6 - 3
=> -2 - 3
= -5 . .. answer
- Anonymous9 years ago
If loga x = 2, loga y = 6, and loga z = â2, then find loga [ (x^2)(z^3 )] / square root[ (y) ]
log [a*b/c] = log a+log b - log c
so,
loga [ (x^2)(z^3 )] / square root[ (y) ] = loga x^2+ loga z^3 - loga y^1/2
= 2 loga x + 3 loga z - 1/2 loga z
= 2*2 + 3* [-2] - 1/2 *6
= 4 - 6 - 3
= 4 - 9
= -5
