joshhaz

any time i try to talk to her about her depression she says "she'll work it out herself" which i think means she won't do crap about it because its her negative self image of herself thats causing the problem

been with her 5 years, she's cool sometimes but really sensitive and irrational

K so someone answered this when i asked this same question before. what i dont get is how they got 820 as the coefficient. how did they get the 820?

So heres how they answered: The only time there is a coefficient of x^39, is when x is to the power of 39, right?

In the binomial expansion, you would need to do:

41C2 * (x)^39 * (-1)^2 = 820 * x^39 * 1 = 820x^39

So the coefficient is 820 :)

Find the coefficient of x^39 in (x-1)^41

help is appreciate, thanks

Use properties of logarithms to find the exact value of the expression log9 27 • log2 8

so i know that log 2 8 can be written log 2 2^3 thus equaling 3, but how do you solve log 9 27?

Solve the equation ex − e−x = 2.

Solve the equation 3e3x = 5 for x.

Solve for x given: log3(x + 1) = 2 + log3 4

If loga x = 2, loga y = 6, and loga z = −2, then find loga [ (x^2)(z^3 )] / square root[ (y) ] .so all those terms are in the same bracket just the x and z term for the numerator and the y term in the denominator, with the log a outside of them

last night i was toking a large blunt and listening to 311 when i came up with this question, man i love marijuana, it smells so good, it tastes good, i love rolling that green gold up and toking a massive blunt while 311 is cranked and i'll pound mike & ikes, yeah?