expanding brackets?? b (b-4)?

b( b - 4)

= b^2 -4b

No, that's not quite right. If we expand the bracket, then we would have to multiply b with b and then b with negative 4:

b(b-4)=

b^2 - 4b

As you can see, the 4 has a minus sign in front, so multiplying a positive letter by a negative number, we get a negative answer.

Hope this helps.

B(b-4) = b x b - 4 x b:

B^2 - 4b

You just distribute the thing outside parenthesis to the terms inside.

b(b - 4) = b(b) - b(4) = b^2 - 4b.

Hope this helps :)

just multiply everything inside bracket by number out side.

ie b^2 -4b

now if you had -b(b-4) answer would be -b^2 + 4b because you are multiplying by -b

You need to time everything inside the brackets by what is outside so

bxb and 4xb

so b^2-4b

Hi, no it would be b squared - 4 because there's a minus sign infront of the 4 making it b*-4

Dear Up All N!ght 182,

b(b-4)

Multiply b by each term inside the parentheses (b-4).

b(b)+b(-4)

Multiply b by the b inside the parentheses.

b*b+b(-4)

Multiply b by b to get b^(2).

b^(2)+b(-4)

Multiply b by the -4 inside the parentheses.

b^(2)-b*4

Multiply -b by 4 to get -4b.

b^(2)-4b

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Thanks

b(b – 4).

= b×b – 4×b

= b² – 4b

----

b(b-4)

=(bxb)-(bx4)

=(b^2)-(4b)

=b^2-4b