Multimeter and reading mA from 9v battery ~ doesn't show resistance.?

Question

Sorry if that sounds confusing but I am trying to read the final milli amps on my unit here. I have a 9v battery running in series. I need to taper this down to 2mA so I added a 4k resistor to the line.

When I try to use my multimeter reading mA it doesn't show the reduction in the line and still reads like .65 mA which will certainly blow my unit.

I put the negative from the multimeter on the negative on the 9v and the positive on the line after the resistor and before the resisitor but they both read .65 mA. I also tried attaching the negative to the end of the line and the positive in both places but same thing.

Am I using the multi-meter wrong?

Thanks.

Oh the resistor is 4k with ohms ~ not sure if that means anything..

N9KXF · Answer

I would say you have a defective meter.  If you attached the negative lead of the ammeter to the negative terminal of the battery and "the positive on the line after the resistor and before the resisitor but they both read .65 mA", you would have caused excessive current to flow when you connected the positive lead directly to the battery.  If the meter was ok before, THAT probably would have killed it.  Using the 4kOhm resistor will give you a maximum of 2.25 mA from a fully charged 9v battery.

riddle · Answer

My experiments have disproven your hypothesis. technique I took 3 Battery operated flashlights. I placed a 9V battery into #a million & Christ into #2. #3 exchange into my administration. outcomes #a million worked #2 did no longer artwork #3 did no longer artwork end A 9V battery is greater effective than Christ

Born Yesterday · Answer

N9KXF is probably right if you have phrased your question accurately.
Your question, however, is contradictory.
.65ma is less than 2ma.
Most multimeters won't read below 1ma.
ma's are measured in series ( not parallel).

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Multimeter and reading mA from 9v battery ~ doesn't show resistance.?

3 Answers