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Basic Factorisation on Algebras?
a) Factorise by extracting common factor
4x+3xy
2ab+3abc-5abd
5rst+3st-2rt
4 Answers
- ?Lv 79 years agoFavorite Answer
4x + 3xy
= x(3y + 4)
2ab + 3abc - 5abd
= ab(3c - 5d + 2)
5rst + 3st - 2rt
= t(5rs + 3s - 2r)
- 9 years ago
For 4x + 3xy,
Since you identified that x is its common factor, the answer is x(4 + 3y)
For 2ab + 3abc - 5abd,
Since you identified that ab is its common factor, the answer is ab(2 + 3c + 5d)
For 5rst + 3st - 2rt,
Since you identified that t is its common factor, the answer is t (5rs + 3s - 2r)
Hope this helped!
Source(s): Myself :D