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Basic Factorisation on Algebras?

a) Factorise by extracting common factor

4x+3xy

2ab+3abc-5abd

5rst+3st-2rt

4 Answers

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  • ?
    Lv 7
    9 years ago
    Favorite Answer

    4x + 3xy

    = x(3y + 4)

    2ab + 3abc - 5abd

    = ab(3c - 5d + 2)

    5rst + 3st - 2rt

    = t(5rs + 3s - 2r)

  • 9 years ago

    For 4x + 3xy,

    Since you identified that x is its common factor, the answer is x(4 + 3y)

    For 2ab + 3abc - 5abd,

    Since you identified that ab is its common factor, the answer is ab(2 + 3c + 5d)

    For 5rst + 3st - 2rt,

    Since you identified that t is its common factor, the answer is t (5rs + 3s - 2r)

    Hope this helped!

    Source(s): Myself :D
  • iceman
    Lv 7
    9 years ago

    x(3y + 4)

    ab(2 + 3c - 5d)

    t(5rs + 3s - 2r)

  • 9 years ago

    x(4+3y)

    ab(2+3c-5d)

    t(5rs+3s-2r)

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